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Induced Voltage in Inductor
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Find Induced Voltage in Inductor

Given a Bushing Current Transformer (BCT) with a shorted secondary terminal. The BCT has 300 milliHenry (mH) rating and it has 0 to 3.5 A or 3500 mA current flowing through it. Assuming an apprentice electrician accidentally remove the shorting wire on the BCT secondary terminal while the circuit was energized at that instant the current is flowing at 5 microsecond and at its maximum value of 3500 mA.

Calculate the induce voltage that the apprentice electrician will be exposed?

Important to remember: Do not remove the shorting wire on any ENERGIZED CT or BCT secondary terminal block because of very High Induced Voltage that can generate an ARC Flash Hazard.

The answer is valid if the units of measurement are in mH, mA, and microsecond. So you need to make measurement conversion to satisfy the calculator algorithm.

V

=

mH * mA microsecond

Why use 5 microsecond? Because that is a reasonable time that can be captured by electronic measuring device. For example in transformer lightning impulse test, 2 microsecond is the minimum time to capture the peak voltage. So using 5 microsecond is a reasonable value.

Another explanation the speed of electron is almost the same as the speed of light which is 300 km per second. In meter the speed of light is 300,000,000 meter per second. It means in 1 meter the electron will only need 1/300,000,000 second or 3.3 nanosecond to travel from point A to point B with 1 meter distance. Since microprocessor wiring connection is less than 1 meter , electronic measuring instrument can record up to 3.3 nanosecond travel time of electrons.

If time is 1 second , enter 1e6. Change 2 to 1e6.

2 microseconds =	2e-6 second
1 Seconds =	1e6 microsecond
0.1 second =	1e5 microsecond
0.01 second =	1e4 microsecond
0.001 second =	1e3 microsecond
1 microsecond =	1e-6 second
1000 microsecond =	1e3 microsecond
1e means	exponent of 10

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