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Motor Formula Reviewer and Interactive Calculator


Credit : Wikipedia.com

Formula memory recall on how to solve the torque generated by a given 5 hp motor at specified motor speed of 1800 rpm.

Torque (lb-ft) Answer
=
HP x 5252

RPM

Formula memory recall on how to solve required motor hp to generate the specified motor torque of 14.59 lb-ft and speed of 1800 rpm.

Torque (lb-ft)
=
HP x 5252

RPM

Formula memory recall on how to solve required motor rpm to generate the specified torque of 14.59 lb-ft and motor 5 hp rating.

Torque (lb-ft)
=
HP x 5252

RPM

Formula memory recall on how to solve motor torque in lb-in generated by the specified motor 5 hp rating and speed of 1800 rpm.

Torque (lb-in)
=
HP x 63024

RPM

Formula memory recall on how to solve motor hp required to generate specified torque of 175.07 lb-in and 1800 rpm speed.

Torque (lb-in)
=
HP x 63024

RPM

Formula memory recall on how to solve motor rpm required to generate specified torque of 175.07 lb-in and motor 5 hp rating.

Torque (lb-in)
=
HP x 63024

RPM

Formula memory recall on how to solve motor synchronous speed generated by specified operational frequency of 60 Hz and number of stator is 4 pole.

Synchronous speed, Ns (rpm)
=
f x 120

P

Formula memory recall on how to solve motor operational frequency required to run at specified 1800 rpm synchronous speed and number of stator pole is 4.

Synchronous speed, Ns (rpm)
=
f x 120

P

Formula memory recall on how to solve motor stator pole to operate at specified frequency of 60 Hz and specified synchronous speed of 1800 rpm.

Synchronous speed, Ns (rpm)
=
f x 120

P

Formula memory recall on how to solve chain tension in lbf to operate at specified chain speed of 10 FPM using specified motor 5 hp rating.

Chain tension in lbf
(pound force)
=
HP x 33000

Chain speed ( FPM )

Formula memory recall on how to solve required motor hp to generate specified chain tension of 16,500 lbf and chain speed of 10 FPM.

Chain tension(lbf =lb force)
=
HP x 33000

Chain speed ( FPM )

Formula memory recall on how to solve required chain speed in FPM using specified motor 5 hp rating to generate specified chain tension of 16,500 lbf.

Chain tension(lbf = lb force)
=
HP x 33000

Chain speed ( FPM )

Formula memory recall on how to solve required belt speed in FPM using specified motor 10 rpm and diameter of belt pulley is 2 inches.

Belt speed (FPM)
=
0.262 x RPM x Diameter( inch)

Formula memory recall on how to solve required belt pulley diameter to meet the specified belt speed of 5.24 FPM and motor 10 rpm.

Belt speed (FPM)
=
= 0.262 x RPM x Diameter
( inch)

Formula memory recall on how to solve required motor rpm to meet the specified belt pulley diameter of 2 inches and belt speed of 5.24 FPM.

Belt speed (FPM)
=
= 0.262 x RPM x Diameter ( inch)

Memory recall foundational knowledge you collected over the years of work experiences:

RPM = revolution per minute ; 1 hp = 33,000 lb-ft per minute ; 1 revolution = 2π
2π = 6.2832 ; 33,000 /6.2832 = 5252 ; 33,000 lb-ft per minute = 396,000 lb-in per min ; 396,000/6.2832 = 63024 ; FPM = feet per min ; FPM = 0.262 RPM * Diameter in inches


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