Formula memory recall on how to solve the torque generated by a given 5 hp motor at specified motor speed of 1800 rpm.
Torque (lbft) Answer
 = 
HP x 5252
RPM

Formula memory recall on how to solve required motor hp to generate the specified motor torque of 14.59 lbft and speed of 1800 rpm.
Torque (lbft)
 = 
HP x 5252
RPM

Formula memory recall on how to solve required motor rpm to generate the specified torque of 14.59 lbft and motor 5 hp rating.
Torque (lbft)
 = 
HP x 5252
RPM

Formula memory recall on how to solve motor torque in lbin generated by the specified motor 5 hp rating and speed of 1800 rpm.
Torque (lbin)
 = 
HP x 63024
RPM

Formula memory recall on how to solve motor hp required to generate specified torque of 175.07 lbin and 1800 rpm speed.
Torque (lbin)
 = 
HP x 63024
RPM

Formula memory recall on how to solve motor rpm required to generate specified torque of 175.07 lbin and motor 5 hp rating.
Torque (lbin)
 = 
HP x 63024
RPM

Formula memory recall on how to solve motor synchronous speed generated by specified operational frequency of 60 Hz and number of stator is 4 pole.
Synchronous speed, N_{s} (rpm)
 = 
f x 120
P

Formula memory recall on how to solve motor operational frequency required to run at specified 1800 rpm synchronous speed and number of stator pole is 4.
Synchronous speed, N_{s} (rpm)
 = 
f x 120
P

Formula memory recall on how to solve motor stator pole to operate at specified frequency of 60 Hz and specified synchronous speed of 1800 rpm.
Synchronous speed, N_{s} (rpm)
 = 
f x 120
P

Formula memory recall on how to solve chain tension in lbf to operate at specified chain speed of 10 FPM using specified motor 5 hp rating.
Chain tension in lbf
(pound force)  = 
HP x 33000
Chain speed ( FPM )

Formula memory recall on how to solve required motor hp to generate specified chain tension of 16,500 lbf and chain speed of 10 FPM.
Chain tension(lbf =lb force)
 = 
HP x 33000
Chain speed ( FPM )

Formula memory recall on how to solve required chain speed in FPM using specified motor 5 hp rating to generate specified chain tension of 16,500 lbf.
Chain tension(lbf = lb force)
 = 
HP x 33000
Chain speed ( FPM )

Formula memory recall on how to solve required belt speed in FPM using specified motor 10 rpm and diameter of belt pulley is 2 inches.
Belt speed (FPM)
 = 
0.262 x RPM x
Diameter( inch)

Formula memory recall on how to solve required belt pulley diameter to meet the specified belt speed of 5.24 FPM and motor 10 rpm.
Belt speed (FPM)
 = 
= 0.262 x RPM x
Diameter
( inch) 
Formula memory recall on how to solve required motor rpm to meet the specified belt pulley diameter of 2 inches and belt speed of 5.24 FPM.
Belt speed (FPM)
 = 
= 0.262 x RPM x
Diameter ( inch)

Memory recall foundational knowledge you collected over the years of work experiences:
RPM = revolution per minute ; 1 hp = 33,000 lbft per minute ; 1 revolution = 2π
2π = 6.2832 ; 33,000 /6.2832 = 5252 ; 33,000 lbft per minute = 396,000 lbin per min ; 396,000/6.2832 = 63024 ; FPM = feet per min ; FPM = 0.262 RPM * Diameter in inches
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