Find the equation of a circle with center (3,4) and point P (-1,3)
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Center (3,4)
( h ,
k )
Point (-1,3) on the radius
( x ,
y )
ANSWER is in generalized equation form of a circle which is: (x - h ) 2 + (y - k) 2 = r 2
First step is to solve for the value of r 2 . How to do that ?
Simply use the given value of x, y and h, k and simplify it to get the value of r 2
(-1-3) 2 + (3-4) 2 = r 2
(-4) 2 + (-1) 2 = r 2
16 + 1 = r 2
You can stop from here as your answer to equation of the circle.
ANSWER, ( x - )2 + ( y - )2 = This radius, is still in the form r2. So take the square root of r,
√ r
to find the actual radius. Click the square root button
of
=
radius
But if the requested solution is equation of a circle in simplified form then you need to expand the two binomial (x - h ) 2 and
(y - k ) 2 then simplified the equation.
ANSWER, x2 - x + y2 - y + + =
ANSWER, x2 - x + y2 - y + =