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Calculate the torque (lb-ft) generated by a given 5 hp motor at specified motor speed of 1800 rpm.
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Torque (lb-ft) Answer
| = |
HP x 5252
RPM
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Calculate the required motor hp to generate the specified motor torque of 14.59 lb-ft and speed of 1800 rpm.
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Torque (lb-ft)
| = |
HP x 5252
RPM
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Calculate the required motor rpm to generate the specified torque of 14.59 lb-ft and motor 5 hp rating.
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Torque (lb-ft)
| = |
HP x 5252
RPM
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Calculate the motor torque in lb-in generated by the specified motor 5 hp rating and speed of 1800 rpm.
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Torque (lb-in)
| = |
HP x 63024
RPM
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Calculate the motor hp required to generate specified torque of 175.07 lb-in and 1800 rpm speed.
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Torque (lb-in)
| = |
HP x 63024
RPM
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The calculate the motor rpm required to generate specified torque of 175.07 lb-in and motor 5 hp rating.
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Torque (lb-in)
| = |
HP x 63024
RPM
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Synchronous speed, Ns (rpm)
| = |
f x 120
P
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Synchronous speed, Ns (rpm)
| = |
f x 120
P
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Synchronous speed, Ns (rpm)
| = |
f x 120
P
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Chain tension in lbf
(pound force) | = |
HP x 33000
Chain speed ( FPM )
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Calculate the required motor hp to generate specified chain tension of 16,500 lbf and chain speed of 10 FPM.
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Chain tension(lbf =lb force)
| = |
HP x 33000
Chain speed ( FPM )
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Calculate the required chain speed in FPM using specified motor 5 hp rating to generate specified chain tension of 16,500 lbf.
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Chain tension(lbf = lb force)
| = |
HP x 33000
Chain speed ( FPM )
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Calculate the required belt speed in FPM using specified motor 10 rpm and diameter of belt pulley is 2 inches.
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Belt speed (FPM)
| = |
0.262 x RPM x
Diameter( inch)
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Belt speed (FPM)
| = |
= 0.262 x RPM x
Diameter
( inch) |
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Belt speed (FPM)
| = |
= 0.262 x RPM x
Diameter ( inch)
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Memory recall foundational knowledge you have collected over the years of work experiences:
RPM = revolution per minute ; 1 hp = 33,000 lb-ft per minute ; 1 revolution = 2π
2π = 6.2832 ; 33,000 /6.2832 = 5252 ; 33,000 lb-ft per minute = 396,000 lb-in per min ; 396,000/6.2832 = 63024 ; FPM = feet per min ; FPM = 0.262 RPM * Diameter in inches
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