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Compute the Height of the Ball
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Compute the Height of the Ball



h(t) = - 16 t 2 + 20 t + 4



When t =
evaluate height (h) when t initial =

h(t) = - 16 t 2 + 20 t + 4

h ( ) = 2 + +

h ( ) = + +

h () = ANSWER: The height of the ball at given initial snapshot of time t = 0.75 second


initial height of ball at h(t = 0) is 4 feet. How do you know it is 4 feet? You refer to the given information of the height equation; h(t) = - 16 t 2 + 20 t + 4 . By substituting in equation t = 0, you will get height , h(t=0) = 4 feet.
Imagine you measure the height from a person's hand holding the ball to the ground before he throws it upward.


SOLVE

and final time, t final =

h ( ) = 2 + +

h ( ) = + +

h ( ) = final height of the ball at final given time, t = 1.25 second


At time = 0.75 seconds, the object is still at the air, the height from the ground is 10 feet.

At time = 1.25 seconds, the object is falling down, the height from the ground is 4 feet


Time (in Seconds) Height(in feet) Δ Height (in feet) / Δ Time (in seconds) Average Rate of Change ΔH /ΔT
0.75 initial 10 initial - - ANSWER
(- 6 / 0.5 = -12)
1.25 final 4 final ΔH = Hfinal - Hinitial ΔT = Tfinal - Tinitial minus - sign, means falling down for direction

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